Introduction
Subspaces
Linear Independence
Coordinates and Basis
Change of Basis
A vector space is a set of objects with two operations: addition and multiplication by a scalar, which satisfy:
1 if u and v in V, u + v in V
2 u + v = v + u
3 u + (v + w) = (u + v) + w
4 0 + u = u + 0 = u
5 u + (-u) = 0
6 if u in V, ku in V
7 k(u + v) = ku + kv
8 (k + m)u = ku + mu
9 k(mu ) = (km)u
10 1u = u
To verify that a set V is a vector space, one can:
1. Identify the set of objects
2. Identify the addition and multiplication by scalar operations in V
3. Verify axioms 1 and 6: closure under addition and closure under multiplication
4. Verify all other axioms
→ Set of real numbers ✓
→ Set of positive numbers ✗
→ Set of vectors of real numbers ✓
→ Set of nxm matrices ✓
A subset W of objects of a vector space V is called a subspace if it is also a vector space
Note that some properties are inherited by the subset
One needs only to verify axioms: 1, 4, 5, and 6
If W is a subset of objects of a vector space V, W is also a vector space if and only if:
Axiom 1 holds for W
Axiom 6 also holds for W
→ A line through the origin in a plane ✓
→ A line that does not cross the origin in a plane ✗
→ A set of all points in a quadrant of a plane ✗
→ Set of diagonal matrices ✓
Given a subset S of vectors in a vector space V as shown below:
\[ S = (\mathbf{w}_{1}, \mathbf{w}_{2}, \mathbf{w}_{3}, \ldots, \mathbf{w}_{r}) \]
The set of all possible linear combinations of S is a subspace of V. We say that S span W
Given a set of vectors S:
\[ S = (\mathbf{v}_{1}, \mathbf{v}_{2}, \mathbf{v}_{3}, \ldots, \mathbf{v}_{r}) \]
S is said to be linearly independent if no vector in it can be expressed as a linear combination of the others
A set of vectors S in a vector space is linearly independent if and only if:
\[ k_{1}\mathbf{v}_{1} + k_{2}\mathbf{v}_{2} + k_{3}\mathbf{v}_{3} + \ldots + k_{r}\mathbf{v}_{r} = \mathbf{0} \]
Only has the trivial solution
Given a set of n vectors for an n-dimensional vector space, one can check if the set is linearly independent:
1. Write the set as a matrix
2. Check if its determinant is nonzero
Coordinate systems can be used to map points into ordered sets of numbers
Examples:
→ Rectangular coordinate systems in 2D
→ Polar coordinate systems in 2D
Frequently, unit perpendicular vectors are used to represent coordinate systems
If S is a set of vectors in a finite-dimensional vector space V, it is called a basis for V if:
(a) S spans V
(b) All vectors in S are linearly independent
Show that both sets of vectors below can form a basis for the 2D space:
\[ \mathbf{u}_{1} = (1, 0),\ \mathbf{u}_{2} = (0,1) \]
\[ \mathbf{u}_{1} = (1, 0),\ \mathbf{u}_{2} = (1,1) \]
If S is a basis for a vector space V, any vector in V can only be represented in exactly one way:
\[ \mathbf{v} = c_{1}\mathbf{v}_{1} + c_{2}\mathbf{v}_{2} + \ldots + c_{n}\mathbf{v}_{n} \]
The set of scalars ci is the coordinate vector of v relative to S
\[ (\mathbf{v})_{S} = (c_{1}, c_{2}, \ldots,c_{n}) \]
Find the coordinates of the point (3, 4), in the following basis:
\[ \mathbf{u}_{1} = (1, 0),\ \mathbf{u}_{2} = (0,1) \]
\[ \mathbf{u}_{1} = (1, 0),\ \mathbf{u}_{2} = (1,1) \]
\[ \mathbf{u}_{1} = (1, 1),\ \mathbf{u}_{2} = (1,-1) \]
Sometimes a change of basis is necessary
Given a set of coordinates in a basis, how can one calculate the set of coordinates in a different basis?
If v is a vector in a space vector V, how are the coordinates [v]B and [v]B' related? B is the old basis and B' the new basis.
The solution is to create a matrix P with the following property:
Each column of P represents the coordinate vectors of the new basis relative to the old basis
This matrix P is called a transition matrix
P maps coordinates in a new basis back to its old basis
\[ \mathbf{u}_{1} = (1, 0),\ \mathbf{u}_{2} = (0,1) \]
\[ \mathbf{u'}_{1} = (1, 0),\ \mathbf{u'}_{2} = (1,1) \]
Any invertible matrix can be shown to be a transition matrix from a basis formed by its columns to the standard basis
If P is the transition basis from B' to B (new basis to old), P-1 is the transition matrix from B to B' (old to new)
A simple way to find P is:
\[ [ \text{new basis} | \text{old basis} ] \xrightarrow{\text{row operations}} [ I | P^{-1} ] \]
Textbook: Sections 4.1, 4.2, 4.3(ignore Functions), 4.4, and 4.6
Exercises
→ Section 4.1: 1, 2, 3, and 9
→ Section 4.2: 1 and 2
→ Section 4.3: 1, 2, and 3
→ Section 4.4: 1, 2, 5, 6, and 7
→ Section 4.6: 1, 2, and 3